Chemical Forums
Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: 12179 on April 06, 2009, 10:58:19 PM
-
I need to prepare 50 mL of "aqueous solution 50mM in SDS and 30 mM in NaCl"
MW of SDS = 288.38g/mol
MW of NaCl=58.44 g/mol
How do I prepare this? I think aqueous means I should dissolve it in water. So SDS in water, then NaCl in water...and then combine it to be 50mL? But then how much water do I dissolve in each? How many grams of each?
Do I prepare 25mL of 50mM SDS and then 25mL of 30mM NaCl and combine them?
Does it matter if it's 10mL of 50mM SDS and 40 mL of 30mM NaCl?
-
If you had 40 ml of a 50 mM solution of SDS, then diluted it to 50 ml, is the solution of SDS still 50 mM?
-
Thanks. Figured it out.