Chemical Forums
Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: science123 on April 24, 2009, 08:02:32 AM
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Given the following data,
H2(g) + 1/2 O2(g) => H2O(g) DGo = -236.0
2 H(g) + O(g) => H2O(g) DGo = -920.8
2 H(g) + 2 O(g) => H2O2(g) DGo = -1,068.0
2 O(g) => O2(g) DGo = -496.6
H2O2(l) => H2O2(g) DGo = 43.1
Determine DGfo for H2O2(l)
Correct : -178.0
I don't know which equations to combine and flip and how do we find the Gf of H2O2 (gas) . I was thinking of someway to find gf of H2O2 gas and subract from Grxn to get Gf of H2O2 liquid. Thanks!
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What's the definition of :delta: Gf?
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What's the definition of :delta: Gf?
Change of Gibbs free energy that accompanies the formation of 1 mole of that substance from it's elements in standard state.
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What's the definition of :delta: Gf?
Change of Gibbs free energy that accompanies the formation of 1 mole of that substance from it's elements in standard state.
Right, so what does that mean, in terms of your reaction?
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Delta Go = sum of Delta Gf of products - sum of Delta Gf of reactants
Am i right?
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Essentially, yes. You're after :delta: Gf for H2O2(l), which is for the reaction H2(g) + O2(g) :rarrow: H2O2(l). Can you find a path using the data you have that allows you to calculate this H2(g) + O2(g) :rarrow: A :rarrow: B :rarrow: C ... :rarrow: H2O2(l)?
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That's that part i am not getting. And btw why does eq. 2 has hydrogen in atomic form?
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You won't necessarily have to use them all (I've not worked it through, so could be wrong here).
For instance, from
H2(g) + 1/2 O2(g) :rarrow: H2O(g) :delta: Go = -236.0
2 H(g) + O(g) :rarrow: H2O(g) :delta: Go = -920.8
H2(g) + 1/2 O2(g) :rarrow: H2O(g) :rarrow: 2 H(g) + O(g)
you can calculate :delta: Gf for 2 H(g) + O(g), by adding equation 1 to the reverse of equation 2; giving 684.8. (Don't forget your units!)