Chemical Forums
Chemistry Forums for Students => Organic Chemistry Forum => Topic started by: scarletthj on April 28, 2009, 06:23:05 AM
-
Hello,
I am having trouble with an assignment.
There are 2 questions i am stuck on which are ~
1. Explain why one isomer of 2-hydroxypropanenitrile is likely to be more toxic than the other
2. Inorganic cyanide in the form of K+ CN- is much more toxic than 2-hydroxypropanenitrile. The cyanide bonds with haemoglobin in blood replacing bonded oxygen and causing death.
Explain the difference in toxicity between the 2 substances.
If anyone can help i would be most grateful!
Thank you.
-
Why is one isomer of any compound likely to have a different effect in vivo than another?
What are the main differences between the cyanide group in KCN and in 2-hydroxypropanenitrile?
-
I think the answer is something to do with the 3D shape connecting to the enzyme molecules?
I'm really struggling on this one.
-
1.) Think R and S stereochemistry.
-
ok, so i think that the arrangement of the atoms differ in the isomers - one is an R configuration and one is an S.
But how does this affect it's toxicity? and which one is the toxic one?
How do i find this information?
Thanks for helping.
-
It would be odd if you had to know which one is more toxic. I think the question was asking in general terms why a given enantiomer would be more toxic.
http://en.wikipedia.org/wiki/Chirality_(chemistry)#In_biology
-
It would be odd if you had to know which one is more toxic.
Agreed to that, perhaps at a higher level you might need to know which enantiomer. Anyway I think you have the essence of the answer, a nuance though - what are the breakdown products, are any of them toxic / involved anywhere in vivo? (You may not need to know this, so feel free to ignore ;) )
-
Thanks to those who helped me, i think i have got the answer sorted now!
I appreciate your help.