Chemical Forums
Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: ItalianChick0188 on May 07, 2009, 12:16:29 PM
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If I titrated 0.0100 M Ce4+ with an unknown substance containing Fe2+ that weighs 0.0249 grams and my equilibrium point is 1.38 mL; How can I find the mmoles of Ce4+ added at the equilibrium point?
Fe2+ + Ce4+ -----> Fe3+ + Ce3+
So far I have 1.50 mL X 0.00001 mmol = 0.000015 mmoles Ce4+ added at equilibrium?
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Equilibrium or equivalence?
http://www.titrations.info/titration-basic-terms#equivalence-point
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Equilibrium or equivalence?
http://www.titrations.info/titration-basic-terms#equivalence-point
equivalence
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I figured it out.
the 0.00015 is the moles of Ce4+ and then converting to mmoles it would be 0.15 mmoles.