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Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: Shaun1979 on June 17, 2009, 10:15:39 AM

Title: Enthalpy of vaporization
Post by: Shaun1979 on June 17, 2009, 10:15:39 AM

Hi,

I have the following question to answer….

The enthalpy change for the vaporization of methanol, CH3OH, at 25 degrees celcius is 37.43 kj/ mol. What quantity of heat energy must be used to vaporize 25.0g of methanol at 25 degrees celcius?

Am I meant to use the Clausius – Clapeyron equation to solve it? I am so confused because in out notes we are told not to study this equation, as it’s not part our current study module, but it’s the only equation that I can think to use?

Can anyone help?

Title: Re: Enthalpy of vaporization
Post by: Astrokel on June 17, 2009, 10:32:48 AM

 :delta: H_vap = Q/n

Title: Re: Enthalpy of vaporization
Post by: Shaun1979 on June 18, 2009, 09:18:24 AM

Oh right...thanks....was digging a bit too deep!