Chemical Forums
Chemistry Forums for Students => Analytical Chemistry Forum => Topic started by: e_spirit on June 18, 2005, 06:58:22 AM
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Hi again :)
I would like you to "push" my solution as I am bit stuck there.
Problem:
Standard solution is made and contains the following data:
0.5021 g ethyl propanoate
0.4927 g propyl ethanoate
4.7243 g acetone (solvent)
The standard solution and the sample are run twice each and the following results are obtained:
Component 1 Determ. 2 Determ. Average of 2 determ.
Area Area
Standard
Ethyl propanoate 525 521 523
Propyl ethanoate 492 487 489.5
Sample
Ethyl propanoate 472 474 473
Propyl ethanoate 380 376 378
Use the external standard method to calculate the content of w/w% ethyl propanoate anw w/w% propyl ethanoate in the sample. Your calculations must be included.
My solution:
1) At first I found average of two determinations
2) I can assume that the volume is 1 L
So C of the standards:
C(ethyl propanoate) = 502.1 mg/L
C(propyl ethanoate) = 492.7 mg/L
3) Calculation of Csample in external standard method is:
C(x) = C(st) * (A(x) / A(st))
so I am calculating concentration of my sample:
C(ethyl propanoate) = 502.1 * (473 / 523) = 454.1 mg/L
C(propyl ethanoate) = 380.5 mg/L
4) w/w% ethyl propanoate anw w/w% propyl ethanoate in the sample.
And here I am stucked. Should I do something with solvent? ???
Thanks in advance!
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What is % w/w concentration? Write down the definition and think - what you know, what you can use?
Beware: you are thinking in categories mg/L. That's not w/w!
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you can convert from C(mg/L) to %w/w by formulas:
C(mol/L)=C(mg/L)/M; M:mol weight(mg/mol).
and then :
C(%)=C(mol/L)*M/(10*d)
d=density of the sample.
HOPE THIS WILL HELP YOU.