Chemical Forums
Chemistry Forums for Students => High School Chemistry Forum => Topic started by: kapital on October 24, 2009, 07:43:48 AM
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I have problems with this: How many grams NaOH we must put in 200mL 1M HCl, if we want to get the solution with pH=13?(alpha=1, volume is not changed)
I start at first how much NaOH neutralize all HCl, that is 8 grams. Now ph=7.
And now ph(x-molar NaOH)=13,5
I have no idea how get x form this. I hope someone can help and really sory form my bad english
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pH + pOH = 14
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I know that. But i sont know how to save this equation -log(x)=13,5
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So you were told to use logarithms but you were not told what they are? Hard to believe.
http://en.wikipedia.org/wiki/Logarithm
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If there would not be minus it woud be 10 ON 13,5=X. Since there is -, i do not know how to do it.
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-log(x)=13,5 => log(x)=-13,5
Does it help? If not, your problem is not chemistry, but math, and you should really spend some time working on it.