Chemical Forums
Chemistry Forums for Students => High School Chemistry Forum => Topic started by: huskywolf on November 01, 2009, 02:38:33 PM
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Hi I have a quick question on this:calculate mol of Fe3O4 formed when:
24g of Fe reacts with 10g of O2 to produce Fe3O4
so Fe3O4= 3Fe +2O2 does this mean that I mutilply the mass of (fe)24g by 3 beacause the coefficent is 3(Mol)and multiply O2 mass(10g) by 2???
or do i keep the original mass so n=34g/232gmol=0.146 mol Fe3O4
0r would it be n=92g/232gmol=0.396 mol Fe3O4
Thanks
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http://www.chembuddy.com/?left=balancing-stoichiometry&right=stoichiometric-calculations
http://www.chembuddy.com/?left=balancing-stoichiometry&right=limiting-reagents
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Sorry that doesnt help me.
I know about mole ratio ,I dont understand if i need to multiply the mass by the coefficents in the question I got
I would be thankful if you could just answer me yes or no?
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Can anybody HELP me with this please?
I am stuck on this ,I need to get my assignment done soon
Please answer yes or no
I cant waste hours looking through unhelpfull sites
surely there are helpful people out there???
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http://www.chembuddy.com/?left=balancing-stoichiometry&right=stoichiometric-calculations
http://www.chembuddy.com/?left=balancing-stoichiometry&right=limiting-reagents
Thanks
It actually helped a bit but I am still not 100%
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you've posted the same question twice and have been given advice to follow. This is a limiting reagent question so start working through it like that.
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This might help:
http://akiscode.com/projects/stoich/