Chemical Forums
Chemistry Forums for Students => High School Chemistry Forum => Topic started by: rossverg on July 03, 2005, 06:55:30 PM
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Hey everyone, I have a question which I think is probably easy but I have no idea how to do it.
I am familiar with the mole concept and I know it applies to this quesiton but I don't know how to answer it. I am also confused whetehr or not to take 1 mole of Nitrogen as 14.01g or 28.02g seeing as though Nitrogren exists as a diatomic molecule.
Calculate the mass of nitrogren in 28.02g of ammonium nitrate.
This is what I have done so far (but I don't know if it is even necessary :S
NH4NO3
Molar Mass = 14.01*2 + 1.008*4 + 16*3
= 80.052g
Then number of moles = mass/molar mass
= 28.02/80.052
= 0.35 mol
But now I'm not sure what to do next....
Thanks to all in advance.
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since u are measuring nitrogen as an atom, not as a gas, u are on the right track. :)
now about the procedure. first find the % mass compostion of N in NH4NO3. which is, the Mr of all the N atoms divided by the Mr of NH4NO3. with the value got, multiply it with the weight of NH4NO3 and your answer is there.
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Oh I see. Thanks for the qyuick reply Xiankai! :D
So this how how I do it:
Mr of NH4NOE
N:H:O
2:4:3
Therefore there are 2/9 Nitrogren atoms
so 2/9 * 28.02
= 6.28g of Nitrogen :-\
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No. You need to use the atomic mass of each atom as you did orginally and then multiply by the weight of the sample.
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u r calculating my mole compositiom and not mass composition like i stated earlier :/
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For every 1 mol of ammonium nitrate there are 2 mol of N. Therefore if you have 0.35 mol of NH4NO3, you will have 0.7 mol of N.
Convert moles to mass.