Chemical Forums
Chemistry Forums for Students => High School Chemistry Forum => Topic started by: positiveion on January 06, 2010, 03:41:52 AM
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I don't know how to do this question mainly because I don't understand the last equation with all its dashes and such. I don't really know where to begin or what to do.
(https://www.chemicalforums.com/proxy.php?request=http%3A%2F%2Fi83.photobucket.com%2Falbums%2Fj283%2Fta_lia%2FUntitled-6.jpg&hash=7ae7ca773093c8f9f6817730b9a31729a7c853a1)
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I have another few questions:
The value of x in Fe(NH4)2(SO4)2.xH2O can be found by determining the amount in moles of sulfate in the compound.
A 0.982 sample was dissolved in water and excess BaCL2 was added. The precipitate of BaSO4 was seperated and dried and found to weigh 1.17g.
Calculate the amount in moles of sulfate in the 0.982g sample of Fe(NH4)2(SO4)2.xH2O
What I have been doing is"
a). no. moles of the entire thing: 0.982 / 284.07 = 0.003456
b). (192.12/284.07) = 0.6763121766 [192.12 is the mass of (SO4)2
c) (a) * (b) =0.002 which i thought was the answer but the answer is actually 0.00501
help, please?
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I don't know how to do this question mainly because I don't understand the last equation with all its dashes and such. I don't really know where to begin or what to do.
(https://www.chemicalforums.com/proxy.php?request=http%3A%2F%2Fi83.photobucket.com%2Falbums%2Fj283%2Fta_lia%2FUntitled-6.jpg&hash=7ae7ca773093c8f9f6817730b9a31729a7c853a1)
Show your attempt. This is an elementary stoichiometry problem.
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I have another few questions:
The value of x in Fe(NH4)2(SO4)2.xH2O can be found by determining the amount in moles of sulfate in the compound.
A 0.982 sample was dissolved in water and excess BaCL2 was added. The precipitate of BaSO4 was seperated and dried and found to weigh 1.17g.
Calculate the amount in moles of sulfate in the 0.982g sample of Fe(NH4)2(SO4)2.xH2O
What I have been doing is"
a). no. moles of the entire thing: 0.982 / 284.07 = 0.003456
b). (192.12/284.07) = 0.6763121766 [192.12 is the mass of (SO4)2
c) (a) * (b) =0.002 which i thought was the answer but the answer is actually 0.00501
help, please?
Start from a balanced reaction
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I don't know how to do this question mainly because I don't understand the last equation with all its dashes and such. I don't really know where to begin or what to do.
(https://www.chemicalforums.com/proxy.php?request=http%3A%2F%2Fi83.photobucket.com%2Falbums%2Fj283%2Fta_lia%2FUntitled-6.jpg&hash=7ae7ca773093c8f9f6817730b9a31729a7c853a1)
Show your attempt. This is an elementary stoichiometry problem.
I don't know what to do because I don't know what the DASHES mean.
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I have another few questions:
The value of x in Fe(NH4)2(SO4)2.xH2O can be found by determining the amount in moles of sulfate in the compound.
A 0.982 sample was dissolved in water and excess BaCL2 was added. The precipitate of BaSO4 was seperated and dried and found to weigh 1.17g.
Calculate the amount in moles of sulfate in the 0.982g sample of Fe(NH4)2(SO4)2.xH2O
What I have been doing is"
a). no. moles of the entire thing: 0.982 / 284.07 = 0.003456
b). (192.12/284.07) = 0.6763121766 [192.12 is the mass of (SO4)2
c) (a) * (b) =0.002 which i thought was the answer but the answer is actually 0.00501
help, please?
Start from a balanced reaction
Fe(NH4)2(SO4)2 + BaCl2 --> BaSO4 + Fe(NH4)Cl2
I'm not sure how to balance that because when I add a 2 in front of BaSO4 then I need to add one in front of BaCl2 and then I need to add one in front of Fe(NH4)2Cl2 and then to Fe(NH4)2(SO4)2 -- then i need to change BaSO4 again and its an endless cycle.
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Fe(NH4)2(SO4)2 + BaCl2 --> BaSO4 + Fe(NH4)Cl2
Fe(NH4)2(SO4)2 + 2BaCl2 = 2BaSO4 + FeCl2 + 2NH4Cl
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I don't know what to do because I don't know what the DASHES mean.
Look in the first few paragraphs of the following
http://www.chemguide.co.uk/organicprops/alkenes/polymerisation.html