Chemical Forums
Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: travibe on July 17, 2005, 12:58:47 PM
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ok im working on this problem about molar concetration and it seems easy enough, i just need a nudge in the right direction...i know the equatio nfor molar concetration is Concentration = Amount of X/Volume of sol'n. but i am given to amounts and not sure which to use....a 50 ml sample with a mass of 50.320g is evap. to dryness, the reulting residue is .453g. Find the molar conc. of the NaCl sol'n. Do i use the evaporated amount of the mass ebfore?
Either way, i get 9.06x10-3g/mL if i use the .453 and 1.0064g/mL if i use the 50.320g. Not sure which way to take it.
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Since when molar concentration is given in g/mL?
http://www.chembuddy.com/?left=concentration&right=molarity (http://www.chembuddy.com/?left=concentration&right=molarity)
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my apologies, i now see that it is mol/l...
Do i ignore the evaporated information? (im assuming not) ... i dont know where to put it in the question to solve for concetration.
btw,
Molarity = Mol/v
Volume = Mol/molarity
Mol = Molarity x Volume
are these conversions right?
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ok tell me if i am on the right track.
Molarity = Mols of Solute/Liter(s) sol'n
.453g of NaCl
Molar Mass of NaCl is 58.48g
.453g/58.48g/mol = .00775 mol = 7.75x10-3mols
Molarity of NaCl = (7.75x10-3 mols NaCl) / .050 L
M = .155 mol/L
Is this anywhere near right?
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OK
Although original data from the question seems to be wrong - mass of the solution should be not 50.320, but 50.230 g. Perhaps a typo?
Checked using CASC in case anybody wonders ;)