Chemical Forums
Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: zxwut? on February 03, 2010, 09:16:34 PM
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He asks:
A solution of 2.500g of BHT in 100.0g of benzene had a freezing point of 4.880 degrees Celcius. What is the molecular mass of BHT?
My first thought was to use MM of solute= [(Kb)(mass solute)(i)] / [(delta Tf)(kg solvent)] but I don't know the differential freezing point temperature. How do I go about finding that or am I totally off base here?
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Your formula seems to be ok except for the fact that Kb has to replaced by Kf, since we are dealing with freezing point depression.
As for the (https://www.chemicalforums.com/proxy.php?request=http%3A%2F%2Fwww.forkosh.dreamhost.com%2Fmimetex.cgi%3F%7B+%5CDelta+T_f+%7D&hash=1b8bec431b8802cc1417909eb7606d0b61087272) part, you have the freezing point of the solution and you can find the freezing point of pure solvent (google/wikipedia-benzene)
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Oh, I see. Thank you very much, sir.
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Dude, I'm just a 17 year old. 8)
You don't have to call me "sir" :P.
Anyway, feel free to ask doubts