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Chemistry Forums for Students => Analytical Chemistry Forum => Topic started by: Passing on March 06, 2010, 06:09:12 PM

Title: Titration of histidine
Post by: Passing on March 06, 2010, 06:09:12 PM

Titration of the trivalent acid histidine (30ml) with NaOH (c=0,1mol/l). Now I need to calculate c(OH^-) in 2 intervals. One from pH 5-6 and the other one from 6.5-7.5.
How do I calculate that? I know the exact amount of leach used at each points.
Normally it's n(NaOH)=c(NaOH)*V(NaOH) but that's only for an equivalence and not a trivalent acid. Do I need the starting volume of 30ml in any way?