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Chemistry Forums for Students => Inorganic Chemistry Forum => Topic started by: Rhonut on April 15, 2010, 02:57:58 PM

Title: Potassium Manganate 7 titration with a mixture of iron 2 and iron 3 sulphates
Post by: Rhonut on April 15, 2010, 02:57:58 PM
Ok, so i have this question i'm doing for revision and i am a bit stuck. The answer on it's own is a bit useless though, i need more how to get to it and why. Anyway, here's the question:

A solution contains iron (ii) and iron (iii) sulphates, 20cm3 of this solution just reduced 19.5cm3 of 0.0200 M Potassium Manganate (vii) in acid solution. After reduction (complete), a further 20cm3 of the solution required 28.7cm3 of the potassium manganate (vii). Calculate the concentration of each sulphate in g.1-1 present in the original solution.

I've started by getting the number of moles of manganate from the first reduction, if that's remotely correct.
Title: Re: Potassium Manganate 7 titration with a mixture of iron 2 and iron 3 sulphates
Post by: BluRay on April 15, 2010, 03:04:51 PM
Sorry, it's a homework...
Title: Re: Potassium Manganate 7 titration with a mixture of iron 2 and iron 3 sulphates
Post by: Borek on April 15, 2010, 05:20:05 PM
What is being oxidized during first titration?

What is being oxidized during second titration?
Title: Re: Potassium Manganate 7 titration with a mixture of iron 2 and iron 3 sulphates
Post by: Rhonut on April 16, 2010, 10:27:44 AM
I'm not quite sure, that is all the information the question gives and there are no questions before that it leads from. I'm assuming the manganate is reduced, and the iron 2 is being oxidized, but how you'd get the concentration of iron 3 i don't know and why two titrations are necessary i don't know. I think the question itself is worded in a confusing way, but all i can do is try to decipher it...   I've come up with some half equations, but not sure if they're the right way to go about this:


I've got the number of moles of manganate used in the first titration as 0.00039 and in the second titration as 0.000574, If that's of any use..
Title: Re: Potassium Manganate 7 titration with a mixture of iron 2 and iron 3 sulphates
Post by: Borek on April 16, 2010, 11:05:31 AM
iron 2 is being oxidized

That's correct. It is oxidzed in both titrations. Do you know why results of both titrations are different? There is a very important hint in the question that explains it.
Title: Re: Potassium Manganate 7 titration with a mixture of iron 2 and iron 3 sulphates
Post by: Rhonut on April 16, 2010, 11:13:49 AM
It's what i'm struggling to understand. I think it may be due to the iron 3 formed during the first oxidation of iron 2, if that makes sense, i'm not sure. Does only the iron 2 get oxidised the first time and the iron 2 and iron 3 get oxidised the second time or something?
Title: Re: Potassium Manganate 7 titration with a mixture of iron 2 and iron 3 sulphates
Post by: Borek on April 16, 2010, 02:53:15 PM
Does only the iron 2 get oxidised the first time and the iron 2 and iron 3 get oxidised the second time or something?

Yes!

Note that original solution contains both Fe2+ and Fe3+ and only Fe2+ can be oxidized. Then you pepare solution for the second titration:

After reduction (complete)

so at this moemnt it doesn't contain Fe3+, as it was all reduced to Fe2+.

You see now what have been titrated in the first titration and what have been titrated in the second?
Title: Re: Potassium Manganate 7 titration with a mixture of iron 2 and iron 3 sulphates
Post by: Rhonut on April 17, 2010, 05:45:42 PM
Ah i think i can see clearly now that the rain has gone, or the Fe3+ rather. The difference in manganate volumes is the amount used to work out how much Fe3+ there was, as the Fe2+ oxidized by that difference in manganate is the amount of Fe3+. I plugged all the numbers in and my answers look relatively within reason, Thanks Borek!