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General Forums => Generic Discussion => Topic started by: World on May 27, 2010, 11:22:43 PM

Title: OMG Help
Post by: World on May 27, 2010, 11:22:43 PM

Anyone that knows graphing really well, can you graph this:
x²-10x-8y+25=0
or
(x-5)²=-8y

Title: Re: OMG Help
Post by: sjb on May 28, 2010, 01:38:51 AM

Which, as your two equations are not identical.

In any event, why not set up a table

x= -10; y = ?
x= -9; y = ?
...

etc

Title: Re: OMG Help
Post by: skyjumper on May 28, 2010, 04:50:22 PM

Start by putting the equation above in standard form. (I just tested on this today :3) Then it will be clearer. (Hint: What is it, an elipse, circle, hyperbola, etc.) and same with the second. (Its parabolic). 

Title: Re: OMG Help
Post by: fish2s on August 10, 2010, 06:03:51 PM

Rearange to give y = 0.125*(x-5)² therefore touches the graph at (5,0) crosses at (0,[25/8]) and is a parabola.

Title: Re: OMG Help
Post by: darko on August 11, 2010, 08:46:06 AM

can you use some of mathematical programs?
(https://www.chemicalforums.com/proxy.php?request=http%3A%2F%2Fimg340.imageshack.us%2Fimg340%2F9972%2F25435879.jpg&hash=590e994eb2a249a82bf0cad6d18f41a37f344d7f),
that is using Mathematica, with very simple program:
f[x_] = (x^2 - 10 x)/8
Plot[f

• , {x, -10, 10}]

You can try with changing of {x,min,max} or use Manipulate function, any other questions?

oh, it is a wrong function it shold be (x^2 - 10 x+25)/8, but principles are the same