Chemical Forums
Chemistry Forums for Students => Physical Chemistry Forum => Topic started by: gio on August 10, 2005, 12:26:40 AM
-
Since I have to prepare an experiment to present in front of the class (laboratory) my teacher told me to do one about Molar Volume in Water.
So I decided to have water at 50ºC and 1 atm, and since I know the density of the water equal to 0.98804g/cm3 and k (kappa)= 4.4*10-10Pa-1. And I want to prove which is the water's molar volume at those conditions :-\.
I investigated that k (kappa) equals to 1/P (pressure). Its hard to know, because I dont know if I assume that is an ideal gas
Thanks for the comments!
-
I may be confused, but how is water an ideal gas?
-
I think I'm wrong...Its not possible to be an ideal gas, indeed ;D
-
That's what we are here for.
To ask you so many questions, that you figure things out yourself. :)
-
But maybe i need someone to guide me on how to solve the question about the molar volume of water, i know that I should use the state equation and there is where k(kappa) appears as the isotermic compresibility, but I dont know how to put the density in that "state equation"
-
I think the liquid state of water at 50ºC. And I think I dont have to count the dependence between k (kappa) with pressure. I'll better rewrite the problem I have now :
Water at 50ºC and 1 atm, density=0.98804 g/cm3 and k(kappa= isotermic compresibility)=4.4x10-10 Pa-1.
a) Which is the molar volume of the water at 50ºC and 1 atm.
-
you don't need kappa. you are given the density of water.
since 1mole of water is 18g, what is the volume of 1mole of water?
-
I think the liquid state of water at 50ºC. And I think I dont have to count the dependence between k (kappa) with pressure. I'll better rewrite the problem I have now :
Water at 50ºC and 1 atm, density=0.98804 g/cm3 and k(kappa= isotermic compresibility)=4.4x10-10 Pa-1.
a) Which is the molar volume of the water at 50ºC and 1 atm.
what exactly does your experiment/project consist of? Is this a homework problem? Try to make your intentions a bit more clear.
Another expression for k is (1/Vm)(RT/P^2)
-
I have to prepare an experiment to present in front of the class (laboratory)
-
perhaps you should do something other than to make water warm, especially in front of a easily distracted audience