Chemical Forums
Chemistry Forums for Students => Inorganic Chemistry Forum => Topic started by: elevation88 on August 31, 2010, 04:51:29 AM
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I am now synthesizing Ru(II)(Bipy)2Cl2 from refluxing Ru(III)Cl3 in DMF in the presence of LiCl and bipyridine. However, I cannot understand what happened in the reduction of Ru(III) to Ru(II). What is the reducing agent? Anybody help me ??? ???
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what happens to the extra chloride anion?