Chemical Forums
Chemistry Forums for Students => Inorganic Chemistry Forum => Topic started by: Questions_14 on September 14, 2010, 08:16:26 PM
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Hi,
Just after some help in regards to the correct equation for the reaction of sulfur dioxide with ferric. I know that the SO2 reduces the Fe3+ to Fe2+ but the equation I came up with didn't look right.
Here is what I got:
SO2 + Fe3+ + H2O :rarrow: Fe2+ + H2SO4 + 2H+
Thanks in advance for any help
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I guess it all happens in water, so you may probably assume you start with SO32-.
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It's not necessary, you can have sulfur dioxide in solution as it is. He only have to look at the O.N. of sulfur and Fe and to understand how many moles of Fe for every mole of SO2 he have to put. Then compute the charge and then hydrogens, adding water somwhere, and it's finished.
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To some extent yes, but if you think about products assuming you end with another electrically neutral molecule in water is ridiculous. Hence I would start with sulfurous, to make my life easier ;)
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To some extent yes, but if you think about products assuming you end with another electrically neutral molecule in water is ridiculous. Hence I would start with sulfurous, to make my life easier ;)
Ah, yes, at least he should have written HSO4- + H+, instead of H2SO4 + H+ :)
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SO2 + 2Fe3+ + 2H2O :rarrow: 2Fe2+ + SO42- + 4H+