Chemical Forums
Chemistry Forums for Students => High School Chemistry Forum => Topic started by: kingkurry on November 02, 2010, 10:18:01 PM
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I need to figure what reaction will occour when Ammonia is poured into a copper(II) nitrate solution. Yes, there is water present. Here is the equation i got, but i feel like i am wrong: 3Cu(NO3)2 + 4NH3OH --> 2Cu(OH)2 + Cu(NH3)4 + 3NO3
I think there is OH because the Ammonia is a base and by defenition would increase the concentration of OH- ions and the copper would naturally bond to these, but im not 100 % sure.
Also is it the Cu(NH3)4 that makes the dark blue color, or is atleast a darker blue than Cu(NO3)2?
Also what exactly is Cu(NH3)4 called?
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[Cu(H2O)4]2+ + 4NH3 = [Cu(NH3)4]2+ + 4H2O
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@AWK : What about the nitrate part? The question does state the presence of nitrate group... So my guess is :
5Cu(NO3)2 + 8NH4OH = 2Cu(OH)2 + 2[Cu(NH3)4](NO3)2
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The nitrates are spectator ions.
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@AWK : What about the nitrate part? The question does state the presence of nitrate group... So my guess is :
5Cu(NO3)2 + 8NH4OH = 2Cu(OH)2 + 2[Cu(NH3)4](NO3)2
Ammonia is the limiting reagents in the complexation reaction. You can expect complex ions with 1-4 ammonia molecules. Only when molar ratio of ammonia:Cu2+ is 2 or slightly greater you can observe nearly quantitative precipitation of Cu(OH)2. Of course, at the some stoichiometries some basic salts can be formed, but I do not know if the copper basic nitrates are poorly soluble (I know for example Cu(OH)2.CuSO4 is insoluble).
At the excess of ammonia nitrate is a spectator ion.
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Guess I didn't know that :-[ :P