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Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: [V] on November 06, 2010, 01:22:17 AM

Title: Q, Kc & Kp Conceptual problem.
Post by: [V] on November 06, 2010, 01:22:17 AM

I am given $$ \Delta H^{\circ} /$$ &  $$ \Delta S^{\circ} /$$, and Temp (K)

I need to calculate $$ K_{p} /$$ at the given Temp (K).
I can solve for  $$ \Delta G^{\circ} /$$
then use this this equation:
$$ \Delta G = \Delta G^{\circ} + RTlnQ /$$

I just set $$ \Delta G=0 /$$ & solve for "Q".

My question is, will this Q value = $$ K_{p} /$$  or $$ K_{c} /$$ ?

Title: Re: Q, Kc & Kp Conceptual problem.
Post by: rabolisk on November 06, 2010, 01:34:41 PM

(https://www.chemicalforums.com/proxy.php?request=http%3A%2F%2Fwww.forkosh.dreamhost.com%2Fmimetex.cgi%3F%7B%2520K_%7Bc%7D%2520%7D&hash=08922b1ff0f76f9e0a42527b044a78b8e0cec884)

There is a conversion between (https://www.chemicalforums.com/proxy.php?request=http%3A%2F%2Fwww.forkosh.dreamhost.com%2Fmimetex.cgi%3F%7B%2520K_%7Bc%7D%2520%7D&hash=08922b1ff0f76f9e0a42527b044a78b8e0cec884) and (https://www.chemicalforums.com/proxy.php?request=http%3A%2F%2Fwww.forkosh.dreamhost.com%2Fmimetex.cgi%3F%7B%2520K_%7Bp%7D%2520%7D&hash=7f1b4393ef2e77976a803df03c64caab96b34388)

Title: Re: Q, Kc & Kp Conceptual problem.
Post by: [V] on November 06, 2010, 01:58:46 PM

Thank you.

I'm reading several different sources, some claim its kc some say its kp.

can you please explain why it is kc?