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Chemistry Forums for Students => Organic Chemistry Forum => Topic started by: Natalie_Noodle13 on January 11, 2011, 12:15:31 PM

Title: Degree level exam question.. Can anyone answer this!? (Acids & bases)
Post by: Natalie_Noodle13 on January 11, 2011, 12:15:31 PM

At 298 K, the Ka for the dissociation of ethanoic acid in water is 1.8 x 10-5 mol dm-3 and the autoprotolysis constant (Kw) of water is 1.0 x 10-14 mol2 dm-6.  Calculate the basicity constant (Kb) of the ethanoate ion in water at 298 K.

I calculated it as;
Ka x Kb = Kw
Kb = Kw/Ka

= 1.0x10-14 / 1.8x10-5 = 5.55x10-10

Is this right?
Thanks :) x

Title: Re: Degree level exam question.. Can anyone answer this!? (Acids & bases)
Post by: Borek on January 11, 2011, 02:17:45 PM

OK. You may have problems if you will have to deal with significant digits fanatic ;)