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Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: Abder-Rahman on February 12, 2011, 07:24:13 AM

Title: What is the oxidizing agent here? And, why?
Post by: Abder-Rahman on February 12, 2011, 07:24:13 AM

If we have the following reduction equation:

O₂ + 4H⁺ + 4e^- -----> 2H₂O

What is the oxidizing agent here? And, why?

Thanks.

Title: Re: What is the oxidizing agent here? And, why?
Post by: opti384 on February 12, 2011, 07:56:48 AM

Do you know what an oxidizing agent is?

Title: Re: What is the oxidizing agent here? And, why?
Post by: Nobby on February 14, 2011, 05:07:00 AM

This is Reduction part of an redox reaction.

The Oxidation part is missing.

Oxygen will be reduced in this case.

Probably H₂  => 2 H⁺ + 2 e^- is a possible Oxidation equation