Chemical Forums
Chemistry Forums for Students => High School Chemistry Forum => Topic started by: LHM on February 13, 2011, 03:21:01 PM
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For the reversible reaction
N2(g) + 3H2(g) ::equil:: 2 NH3(g)
the rate of the forward reaction is much larger than the rate of the reverse reaction when:
A) there is an excess of NH3 and little N2 and H2
B) the reaction is at equilibrium
C) NH3 is present but no H2 and N2 are present
D) N2 and H2 but no NH3 are present
The answer is A but it hasn't always been so reliable so is this really the answer? If so, why? Why isn't the answer D since if there's only N2 and H2 then shouldn't the rate of the forward reaction be greater?
Also as a side question, since I started thinking about it just now, if the above reaction is at equilibrium and you add N2 to the system, would the rate of the forward reaction increase? And would the rate of the reverse reaction decrease too along with the rate of the forward reaction increasing?
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The answer is D for all the reasons you stated.
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I agree with rabolisk. The answer is definitely D.
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ya i agree
the answer has to be D.