Chemical Forums
Chemistry Forums for Students => Analytical Chemistry Forum => Topic started by: ciel on September 11, 2005, 08:50:58 PM
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1.) What are the products of this reaction?
THAM + HCl -->
(HOCH2)3-C-NH2 + HCl -->
I think THAM would be (HOCH2)3-C-NH3+ and HCl would be Cl-
but then, what would happen to H+ in (HOCH2)3 ?
2.) In the reaction of KHP + NaOH, KHP would lose H+ and K+
How could it happen? (I really don't know how it could be like that)
Thanks.
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1.) What are the products of this reaction?
THAM + HCl -->
(HOCH2)3-C-NH2 + HCl -->
I think THAM would be (HOCH2)3-C-NH3+ and HCl would be Cl-
but then, what would happen to H+ in (HOCH2)3 ?
THAM is a base containing only one basic group, hence
THAM + HCl = (HOCH2)3-C-NH3+ (aq) + Cl-(aq)
is the only reaction in water solution
2.) In the reaction of KHP + NaOH, KHP would lose H+ and K+
How could it happen? (I really don't know how it could be like that)
Thanks.
Hint!
KHP (potassium hydrogen phtalate) ia a monoprotic acid salt
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thanks :D