Chemical Forums
Chemistry Forums for Students => High School Chemistry Forum => Topic started by: THISMOMENTISFATE on March 14, 2011, 09:13:06 PM
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Write down the reaction between 1-pentyne and 2 molar HBr?
http://img718.imageshack.us/i/triple2.jpg/
should there be 2 br or 4?
should i have drawn 2 brs attacking in the middle step? or should there be four steps?
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First Reaction R-CCH + HBr => R-CBr=CH2
Second Reaction: R-CBr=CH2 + HBr => R-CBr2-CH3
Law of Markownikov
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why R-CCH doesnt it have to be 1-pentyne??
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1-Pentyne is CH3CH2CH2-CCH
With R = n-Propyl CH3CH2CH2- we got R-CCH
Ni zhidao?
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oh ok, our teacher hasnt taught us that yet, we stil write out all the ch's