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Chemistry Forums for Students => Physical Chemistry Forum => Topic started by: vasu on March 25, 2011, 07:55:10 AM

Title: The electronic transition in hydrogen atom
Post by: vasu on March 25, 2011, 07:55:10 AM

Q1. The electronic transition in hydrogen atom which accompanied by maximum release of energy is.

Answer: n=2 to n=1.

Pls Explain why?

Q2.For the hydrogen atom, the energy of electron is -13.58/n2 eV. The minimum quantity of energy which it can absorb in its ground state is

Answer: 10.19 eV,

Explain pls,,,

Title: Re: The electronic transition in hydrogen atom
Post by: Schrödinger on March 25, 2011, 09:14:27 AM

Q1. Use the expression for energy of electron given in Q2. You will find that the difference in energy between subsequent energy levels decreases as you move further away from the nucleus. i.e, |E1-E2|>|E2-E3|>|E3-E4|... and so on

Q2. Compute E1 and E2.

Reply to this post if you can't understand why we do this. I'll give you a diagrammatic explanation

Title: Re: The electronic transition in hydrogen atom
Post by: vasu on March 25, 2011, 09:59:31 AM

thanx
please post that diagram

Title: Re: The electronic transition in hydrogen atom
Post by: Enthalpy on April 05, 2011, 11:29:03 AM

Why should it be n=2 to n=1? A transition from a nearly-free orbital to n=1 will give nearly 13.6eV.
With the next advantage of being an allowed transition. 2s to 1s can't work by emitting a photon because of momentum conservation.

Good not to be a student any more.