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Chemistry Forums for Students => High School Chemistry Forum => Topic started by: Master_Key on July 07, 2011, 09:08:28 AM

Title: Red Lead
Post by: Master_Key on July 07, 2011, 09:08:28 AM
Red Lead Pb3O4 :- What is the ratio of Pb +2 and +4 oxidation states in this.
If you find any links then please give it.
Title: Re: Red Lead
Post by: sjb on July 07, 2011, 10:16:17 AM
Red Lead Pb3O4 :- What is the ratio of Pb +2 and +4 oxidation states in this.
If you find any links then please give it.

If it were solely lead (II), what would the formula of the oxide be? What about if it were solely lead (IV)?
Title: Re: Red Lead
Post by: Vidya on July 07, 2011, 11:26:18 AM
2PbO·PbO2.
 :)
Title: Re: Red Lead
Post by: Master_Key on July 08, 2011, 08:46:09 AM
I meant that I have read that Pb3O4 is a mixture of PbO and PbO2 So what is the ratio of these in the mixture.

Pb3O4 Can carry out the reactions of PbO and PbO2 so i need to find the ratio of +2 and +4 in this.
Title: Re: Red Lead
Post by: sjb on July 08, 2011, 09:29:23 AM
I meant that I have read that Pb3O4 is a mixture of PbO and PbO2 So what is the ratio of these in the mixture.

Pb3O4 Can carry out the reactions of PbO and PbO2 so i need to find the ratio of +2 and +4 in this.

OK, so you can set up two equations x + y = 3 (for atoms of lead) and x + 2y = 4 (for atoms of oxygen), where x is the amount of lead (IV) oxide and y the amount of lead (II) oxide...

Of course, in this case it's relatively easy by trial and error....
Title: Re: Red Lead
Post by: Master_Key on July 09, 2011, 08:10:00 AM
I meant that I have read that Pb3O4 is a mixture of PbO and PbO2 So what is the ratio of these in the mixture.

Pb3O4 Can carry out the reactions of PbO and PbO2 so i need to find the ratio of +2 and +4 in this.

OK, so you can set up two equations x + y = 3 (for atoms of lead) and x + 2y = 4 (for atoms of oxygen), where x is the amount of lead (IV) oxide and y the amount of lead (II) oxide...

Of course, in this case it's relatively easy by trial and error....
Thank you. I got it.