Chemical Forums
Chemistry Forums for Students => Analytical Chemistry Forum => Topic started by: kapital on September 03, 2011, 06:28:42 AM
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How can you preprare 500 ml buffer from 0,600 M H3PO4 and 3,00 M NaOH.(pH=3)
pKa1=2,148
[H2PO4-]/[H3PO4]=Ka1/[H30+]=7,11
Out of there I get 293,3 ml NaOH and 206,61 ml of H3PO4, but thats wrong, why?
(There is not mistake that Ka2 and Ka3 of phosporic acid arent give, its simplifed)
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How can you preprare 500 ml buffer from 0,600 M H3PO4 and 3,00 M NaOH.(pH=3)
pKa1=2,148
[H2PO4-]/[H3PO4]=Ka1/[H30+]=7,11
Out of there I get 293,3 ml NaOH and 206,61 ml of H3PO4, but thats wrong, why?
(There is not mistake that Ka2 and Ka3 of phosporic acid arent give, its simplifed)
I have not done the maths here, but are you taking into account the concentrations of acid and base? Seems to me that a mixture as you describe will be heavily basic?
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From that equation I get the base/acid ratio, than from eqution V(base)=500-V(acid) I get the results. ??
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From that equation I get the base/acid ratio, than from eqution V(base)=500-V(acid) I get the results. ??
Molar ratio, yes, not volume ratio.
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Yes I know that. Can you please tell me how can I solve this exercise?
(What I am not completly sure, but does a reaction make any importance?
Since only first dissociation constant matter I write reactions as
H3PO4 + NaOH --> NaH2PO4 + H20)
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Your reaction is correct.
You have a system of several equations. HH gives you molar ratio of the acid and conjugate base. You know sum of volumes must be 500 mL. These are two equations. Try to express final concentrations of acid and conjugate base using known concentrations, known final volume and two variables - VNaOH and VH3PO4. Solve.
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I tried that, I get the same results. I tried everthing I can think off. I dont know what is wrong.
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Show your work then, and we will look for errors.
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Ok. And I have another(2) one, the exercise is:
2. How many ml 0,1000 M HCl and how much g Na-acetate dihydrate is needed for 250 ml buffer , pH 5,00 (5 C) and ionic strnght 0,100 M ?
pKw (5 C) = 14,734
pKa (5 C) = 4,77
Na=23
The amaunt of sodium acetate dihydrate is calculated corect, the amaunt of HCl is not.
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2
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When calculating concentration of phosphoric acid you have to take into account fact that part of it was neutralized.
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How can I do that? And what abaut the second?
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Can anabody please tell me how can I solve this two exercises, perhaps in some other way?
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There is no other way. The way you tried you are assuming concentration of phosphoric acid is that of the acid that was put in the solution - but part of it was neutralized to H2PO4-, so you have to subtract neutralized amount from the amount that was put into the solution. This is all in the neutralization stoichiometry.
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Can you show that please?
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Geez, stop whining, start trying.
Assume volume of the acid and volume of the base are VNaOH and VH3PO4. Use these volumes to write formulas for:
Number of moles of the acid present initially.
Number of moles of the acid that were neutralized.
Number of moles of the acid that were left (hint: use formulas written above)
Final concentration of the acid.