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Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: gakgx6 on September 26, 2011, 10:48:00 AM

Title: How to make a 1%, acetic acid 1% chitosan solution from 0.2 M acetic acid?
Post by: gakgx6 on September 26, 2011, 10:48:00 AM

0.2 molar acetic acid- % solution=Molarity x molecular weight/10=0.2 x 60/10=1.2%.
1.2 gram of acetic acid per 100 ml water. If I add 20 ml of water, then I have 1.2 gram acetic acid per 120 ml water=1% acetic acid. How do I figure out how much of chitosan i need to add?

I was thinking to add 1 gram chitosan, am I correct?

Title: Re: How to make a 1%, acetic acid 1% chitosan solution from 0.2 M acetic acid?
Post by: Borek on September 26, 2011, 11:49:39 AM

1g per 120mL (more or less 120g) will be not 1%, more like 0.8%.

Title: Re: How to make a 1%, acetic acid 1% chitosan solution from 0.2 M acetic acid?
Post by: gakgx6 on September 26, 2011, 12:58:16 PM

Quote from: Borek on September 26, 2011, 11:49:39 AM

1g per 120mL (more or less 120g) will be not 1%, more like 0.8%.

Sorry I meant 1.2 gram. Will my method be the right one to make the 1% acetic 1% chitosan?

Title: Re: How to make a 1%, acetic acid 1% chitosan solution from 0.2 M acetic acid?
Post by: Borek on September 26, 2011, 02:40:15 PM

To be exact you should take even a little bit more than 1.2g, as final mass will be 120g plus the mass of chitosan added, so the concentration will be 1.2/(120+1.2)*100%. But the error is so small you can safely ignore it. Your method looks reasonably good.