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Chemistry Forums for Students => High School Chemistry Forum => Topic started by: rayyau35 on November 20, 2011, 05:07:58 AM

Title: chemical equilibrium
Post by: rayyau35 on November 20, 2011, 05:07:58 AM

2.00L flask was filled with 2.00 moles of SO2 gas and 2.00 moles of NO2 gas and heated.After equilibrium was reached at 400 DEGREE C,it was founded that 1.30 moles of NO gas was present.The reaction occurring is represented by the following equation.
SO2+ NO2 ----->SO3 +NO

1.Calculate the value of the equilibrium constant.K for this reaction.
2.Calculate the value of the equilibrium constant K" at 400C,for the reaction shown below:
  SO3+NO------->SO2+NO2

Title: Re: chemical equilibrium
Post by: sjb on November 20, 2011, 06:52:51 AM

Quote from: rayyau35 on November 20, 2011, 05:07:58 AM

2.00L flask was filled with 2.00 moles of SO₂ gas and 2.00 moles of NO₂ gas and heated.After equilibrium was reached at 400°C,it was founded that 1.30 moles of NO gas was present.The reaction occurring is represented by the following equation.
SO₂+ NO₂  :rarrow: SO₃ +NO

1.Calculate the value of the equilibrium constant.K for this reaction.
2.Calculate the value of the equilibrium constant K" at 400°C,for the reaction shown below:
  SO₃+NO------->SO₂+NO₂

If there are now 1.30 mol of NO, how much SO₃ is there? If you started with 2.00 mol of SO_2, how much is there left?

Title: Re: chemical equilibrium
Post by: Vidya on November 20, 2011, 07:46:35 PM

you know the moles of NO reacted so you calculate the equilibrium moles of each of the reactant from the balanced equation.Divide these moles with volume of the container to get the concentrations of each of the substance(reactant and products) at the equilibrium.Now you can use formula the calculations of K(equilibrium constant).