Chemical Forums
Chemistry Forums for Students => Organic Chemistry Forum => Topic started by: Zainb on January 31, 2012, 12:55:10 PM
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The combination of potassium permanganate and active manganese dioxide (KMnO4/MnO2) produces a reagent that can be used effectively for the oxidation of alcohols to carbonyl compounds as shown below.
(https://www.chemicalforums.com/proxy.php?request=http%3A%2F%2Fwww.organic-chemistry.org%2Fabstracts%2Fliterature%2F814c.gif&hash=d54aa67c739c68f5d2cdb1c4626b2afe95fa561b)
Any idea about the resulting reagent from this combination?
Usually KMnO4 is used to oxidize alkenes.
Thanks for any help..
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The combination of potassium permanganate and active manganese dioxide (KMnO4/MnO2) produces a reagent that can be used effectively for the oxidation of alcohols to carbonyl compounds as shown below.
(https://www.chemicalforums.com/proxy.php?request=http%3A%2F%2Fwww.organic-chemistry.org%2Fabstracts%2Fliterature%2F814c.gif&hash=d54aa67c739c68f5d2cdb1c4626b2afe95fa561b)
Any idea about the resulting reagent from this combination?
Usually KMnO4 is used to oxidize alkenes.
Thanks for any help..
I see you obtained this from the following paper. The title says it all!
I guess it is not a reagent but a supporting medium, similar to Pd/C.
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I have seen the complete paper,,, but they did not explain the mechanism...
They used 17.3 equivalents from MnO2 and just 32 equivalents from KMnO4,,, Then the permanganate just a catalyst,,, I try to use this regent on alkenyl compound but the reaction mechanism still unclear.
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I have not seen the paper. I don't know that the mechanism for KMnO4 oxidations of benzylic CH's has been proven, but it is generally believed to involve a radical reaction. From there, oxidation reactions generally involve
H-C-O-X :rarrow: H+ + C=O + X-
where X is any group able to accept electrons, MnOn, CrOn, Br, Cl, Ag, etc.
Although the first step is usually carried out a elevated temperatures (to improve radical formation?), the reference reaction was carried out under mild conditions. If your substrate fails to react, I should presume the radical allylic oxidation step has a higher activation energy than is being supplied in this reaction. (If you have an alkene, I am surprised the hydroxylation reaction (similar to OsO4 oxidation) is not occurring directly.)
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the hydroxy group is a good nucleophile, which will attack the metal atom centr in the MnO2 (SN2) and then one of oxynium atom of the intermediate, R2-CH-O-MnO2H, will depronate the proton in the cyclic transition state leading to the carbony compound