Chemical Forums
Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: Violet89 on February 13, 2012, 05:14:23 AM
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If a sample of butane, C4H10, contains a total of 8.0 X 10^3 atoms of carbon, how many molecules of butane are in the sample?
8.0 X 10^3 atoms C * (1 formula unit C4H10 / 4 C atoms) * (6.022 X 10^23 C4H10 molecules / 1 formula unit C4H10) = 1.2 X 10^27 molecules C4H10
Is this correct?
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If a sample of butane, C4H10, contains a total of 8.0 X 103 atoms of carbon, how many molecules of butane are in the sample?
8.0 X 103 atoms C * (1 formula unit C4H10 / 4 C atoms) * (6.022 X 1023 C4H10 molecules / 1 formula unit C4H10) = 1.2 X 1027 molecules C4H10
Is this correct?
Not quite, no. Why have you multiplied by Avogadro's number (what are it's units?)
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If a sample of butane, C4H10, contains a total of 8.0 X 103 atoms of carbon, how many molecules of butane are in the sample?
8.0 X 103 atoms C * (1 formula unit C4H10 / 4 C atoms) * (6.022 X 1023 C4H10 molecules / 1 formula unit C4H10) = 1.2 X 1027 molecules C4H10
Is this correct?
Not quite, no. Why have you multiplied by Avogadro's number (what are it's units?)
Thanks for the reply. Would you simply divide 8.0 X 10^3 by 4 then?
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Yes.
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Yes.
Thank you. :)