Chemical Forums
Chemistry Forums for Students => High School Chemistry Forum => Topic started by: konkani1kaiser on November 01, 2005, 08:31:40 PM
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Hey i just cant get this question, some help please.
The density of a liquid nitrogen is .808g/mL at 77K. What volume of nitrogen gas at stp, must be liqufied to make 10.0L of liquid nitrogen?
I tried finding moles nitrogen for some reason, but my answer was unhelpful, and i dont the the ideal will help here. Please can someone help.
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If its density is 0.808g.mL-1 --> 808g.L-1 in 10 litres ----> 8080g
PV=nRT
--> V = mRT/MP
you know: m, R, T, M, and P :)
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what would M be, also i get V = 3648.5L, not quite right?
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V = mRT/MP
m = 8080g
R = 0.0821L.atm.K-1.mol-1
T = 273K
M = 28g.mol-1
P = 1atm
V = 6468L