Chemical Forums
Chemistry Forums for Students => Inorganic Chemistry Forum => Topic started by: Winga on November 14, 2005, 01:45:08 PM
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e.g. a square planar complex
For dxz,dyz ---> dz2 transition, if there is no electron in dz2 orbital of metal centre, when a solvent molecule acts as a ligand to attach the metal centre at z-axis, then, the dz2 is stablized or destabilized?
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I'd put destablized. dz2, its spatial arrangement causes repulsion with ligand electrons
Hey wait, square planar, how come d2 is involved?
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If there is no electron in dz2, how comes the electron-electron repulsion with ligand's lone pair.
You mean the empty dz2 orbital repels ligand's lone pair?
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sorry, I was talking about octahedral. I reconsidered it, maybe only dx2-y2 has repulsion. After splitting all other orbitals are stablized.
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I just wonder that there is destabilization of filled dz2 orbital when a ligand attaches to the metal centre at z-axis, while there is stabilization of unfilled dz2 orbital when a ligand attaches to the metal centre at z-axis.
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Can anyone help?
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the crystal field arises as a result of the inherant geometry of the system whether or not the orbitals are filled. The crystal field splitting diagram for a five coordinate square pyramidal complex looks similar to square coordinate complexes but the energy of the z2 orbital is higher than it is in the square planar complex as a result of interaction with the new ligand.