Chemical Forums
Chemistry Forums for Students => Organic Chemistry Forum => Topic started by: Hubert on November 19, 2005, 11:27:03 AM
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how oxidation work in hydrocarbon in the presence of KMnO4. For e.g this.
cyclohexene + KMnO4 = cis-1,2-cyclohenanediol
i tot oxidation onli works when it removes one hydrogen atom from a hydroxyl grp attached to the carbon and another hydrogen attached to the same carbon...so how does this work from this equation i wrote above
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cis means they are both on the same side
you go through a cyclic ester
you end up with Mn(V) in MnO3- (which will disproportionate and react again)
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Hubert: Spell check your posts and write better topic subjects or be banned. Review forum policy on how to write subjects titled "Read This Before Posting!"
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hey...ok...now this is the part...oh...where did the hydrogen come from....how cum it attaches to the oxgen atom form nowhere
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and to what i learn in class...oxidation only involve the lose of a hydrogen attached to the carbon and a hydrogen of a hydroxyl grp attached to the same carbon...then how did oxidation work in the above diagram...sorrie...i'm realli confused
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see if this sheds any light on things
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i mean with only cyclohexene and pottaium permanganate...how do they oxidise to becum an alcohol?
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To quote the poet, 'Water,water, water, nor any drop to drink!'
Water plays its role in this reaction by 'giving' H-atoms to the diol. Arsenic posted a complete mechanism for this reaction, where you can appreciate how water 'completes' the diol.
Not only does water take part in the reaction: also OH- does it!
However, if you want to see the electrons moving, look at the arrows (every arrow is a couple of electrons)