Chemical Forums
Chemistry Forums for Students => Organic Chemistry Forum => Topic started by: rleung on November 20, 2005, 03:54:32 PM
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Hi,
If you react 3-iodo-4-methylheptane in an E1 fashion, would you get 3-methyl-3-heptene AND 4-methyl-3-heptene? The book says that we only get the first product (methyl shift), but isn't it also possible to perform a hydride shift and get the second product? Thanks.
Ryan
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why does it do a methyl shift at all
isn't the resulting cation secondary just as the first one was?
in my eyes it gets more stable only with hydride shift
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I think it'll do a hydride shift first in order to make a tertiary cation.
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What's the solvent of the reaction???