Chemical Forums
Chemistry Forums for Students => Organic Chemistry Forum => Topic started by: shalikadm on June 02, 2012, 02:39:31 AM
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We have taught that there must be a directly bound H atom to the C atom which is bound to the benzene ring to oxidize alkylbezene(benzene ring-CH3) with strong oxidants (H+/KHmO4 heat )unlike non-alkylebenzene(benzene ring-C≡CH)
1.Do we need such thing (a directly bound H atom to the C atom which is bound to the benzene ring) to oxidize alkylbezene with alkaline KMnO4 to get benzoate ion ?
2.It says that we can oxidize toluene with soft oxidants (MnO2) to get benzaldehyde.Can we get benzaldehyde from any alkyl or non-alkyl benzene with soft oxidants ?
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We have taught that there must be a directly bound H atom to the C atom which is bound to the benzene ring to oxidize alkylbezene(benzene ring-CH3) with strong oxidants (H+/KHmO4 heat )unlike non-alkylebenzene(benzene ring-C≡CH)
1.Do we need such thing (a directly bound H atom to the C atom which is bound to the benzene ring) to oxidize alkylbezene with alkaline KMnO4 to get benzoate ion ?
2.It says that we can oxidize toluene with soft oxidants (MnO2) to get benzaldehyde.Can we get benzaldehyde from any alkyl or non-alkyl benzene with soft oxidants ?
1. Yes you require a CH species on the carbon attached to the aromatic ring.
2. The benzylic carbon atom will be the one which is oxidized, all other things being equal. MnO2 should do this and stop without further oxidation to the acid.
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thanks for the quick reply
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Thank you, this was helpful for me, too.