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Chemistry Forums for Students => Inorganic Chemistry Forum => Topic started by: victor on December 03, 2005, 08:04:54 AM

Title: Oxalic acid
Post by: victor on December 03, 2005, 08:04:54 AM
anyone know what is the type of reaction (is it redox??) between:
Oxalic acid (HOOC-COOH) with Pottasium permanganate (KMnO4)? and what is the product from this reaction??
I've search it in my organic chemistry book and I find that carboxylic acid is impossible to be oxidized again....but KMnO4 itself is one of the oxydator...and the reacton is working with the color change from deep purpple to deep yellow and then continue till colorless....
Title: Re:Oxalic acid
Post by: Borek on December 03, 2005, 08:22:18 AM
(COO)22- -> 2 CO2 + 2e-

http://www.chemicalforums.com/index.php?board=8;action=display;threadid=5158;start=msg22934#msg22934 (http://www.chemicalforums.com/index.php?board=8;action=display;threadid=5158;start=msg22934#msg22934)
Title: Re:Oxalic acid
Post by: Beatles on December 04, 2005, 03:46:01 AM
Quote
(COO)22- -> 2 CO2 + 2e-

Wrong! formula of oxalate is C2O42-
Title: Re:Oxalic acid
Post by: Alberto_Kravina on December 04, 2005, 03:51:14 AM
It is the same!

The oxalic acid is two carboxyl groups bound together (COOH)2. The formula of oxalate can be (COO)22- or C2O42-
   O          O
    \\       //
     C ---C
    /        \
HO          OH

The underlined H Atoms are the acidic H

Typo corrected - C2O42-, not C2H42-, Borek
Title: Re:Oxalic acid
Post by: Beatles on December 04, 2005, 10:00:33 AM
Ups sorry didn't notice it's the same.
How can Borek edit alberts messages?
Title: Re:Oxalic acid
Post by: Borek on December 04, 2005, 11:05:02 AM
Quote from: Beatles on December 04, 2005, 10:00:33 AM
Ups sorry didn't notice it's the same.
How can Borek edit alberts messages?

See the sign below my name?
Title: Re:Oxalic acid
Post by: victor on December 05, 2005, 08:03:16 AM
Ok, thanks for the info....all of you really help me in making lab report... ;D