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Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: FLgirl on October 16, 2012, 06:47:36 PM

Title: Solution stoichiometry... mass in grams?
Post by: FLgirl on October 16, 2012, 06:47:36 PM

"What volume (in mL) of a 0.150 M HNO3 solution will completely react with 35.7 mL of a 0.108 M Na2CO3 solution according to the following balanced equation:

Na2CO3 + 2 HNO3 ---> 2 NaNO3 + CO2 + H2O

In the reaction above, what mass (in grams) of carbon dioxide forms?"

The first part I solved, but how do I calculate the mass(g) of carbon dioxide?

Title: Re: Solution stoichiometry... mass in grams?
Post by: BetaAmyloid on October 16, 2012, 07:03:41 PM

If you know the volume of HNO3 that completely reacts with Na2CO3, then you know that both react completely and there really is "no" limiting reactant. That being so, you can take either the volume of HNO3 or Na2CO3, and given there molarities:

1) calculate the moles of either HNO3 or Na2CO3
2) use a molar ratio between either HNO3 or Na2CO3 and CO2
3) multiply by the molar mass of CO2 to get to grams of CO2

Note: Make sure your units are correct, is molarity mol/mL or mol/L? Are your volumes in mL or L? Make sure the units match up.

Title: Re: Solution stoichiometry... mass in grams?
Post by: FLgirl on October 16, 2012, 07:30:17 PM

Thank you so very much.