Chemical Forums
Chemistry Forums for Students => High School Chemistry Forum => Topic started by: Mr. Raru on December 28, 2005, 09:36:44 PM
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Is it true that sulfide is oxidized to sulfate while H2S is oxidized to S8? Why is this so when both have an oxidation number of 2 to begin with?
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In what reaction?
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A solution of copper(II) sulfide is oxidized by dilute nitric acid.
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Hmmm...solution of copper sulfide? copper sulfide has apretty low solubility product (Ksp(CuS) = 1.3×10-3 6)
Sulfide is partially oxidized to sulfate with dil. nitric acid.
H2S is oxidized to S8 with oxygen:
8 H2S + 4 O2 ----> S8 + 8 H2O
Why is this so when both have an oxidation number of 2 to begin with?
I don't know if I understood the question, but I think that it depends on the strength of the oxidation agent.