Chemical Forums
Chemistry Forums for Students => High School Chemistry Forum => Topic started by: kumquat on January 11, 2006, 03:51:49 PM
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The question I'm stucked on is:
If the concentration of Ox- is .350M, how much excess Ox- (in moles) would be added to 25.00mL of a 0.0150M solution of Al^+3?
This would be a mol:mol ratio, right?
I got my eq.: Al^3+ + 3Ox- --> Al(Ox)3.
I did: .0150M/0.0250L and then 3mol Ox/1mol Al...then I'm stucked.
What confuses me is the 0.350M because I do know how to use this data. Is this extra info that I don't need? If it is extra, then I'm done at the mol:mol, right?
Oh, Ox- is 8-hydroxyquinolinate, not Oxalate. ( but that doesn't really matter, I don't think)
Thanks in advance for any help.