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Chemistry Forums for Students => Inorganic Chemistry Forum => Topic started by: mr.fuscoII on January 14, 2006, 04:49:34 PM

Title: Nernst Equation
Post by: mr.fuscoII on January 14, 2006, 04:49:34 PM

For standard temperatures, E = Estandard -0.0591/n

How do you get 0.0591?       E = Estandard = RT/nF.....R = 8.31, F = 96 485, T = 298....my math can't take
                                                                                                                            me there

Title: Re:Nernst Equation
Post by: Borek on January 14, 2006, 05:47:20 PM

Take a look at both equations - one calls for ln, second for log. You are probably missing conversion factor.

Title: Re:Nernst Equation
Post by: mr.fuscoII on January 14, 2006, 06:12:14 PM

I looked it up further, ln(x) = 2.303log(x), that is that conversion factor we were missing. Thanks