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Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: Tom on June 18, 2004, 04:29:08 PM

Title: Reaction A+B ->C
Post by: Tom on June 18, 2004, 04:29:08 PM

a reaction A + B -> C is second order in A and first order in B, what will cause the rate to increase by a factor of 42?

double (A) and keep (B) constant is what I concluded, any other opinions?

Title: Re:Reaction A+B ->C
Post by: Donaldson Tan on June 19, 2004, 11:54:50 AM

Your suggestion suggest that the rate equation is defined as:
reaction rate = k[A]²

You are right, if the factor is 4, not 42.

Title: Re:Reaction A+B ->C
Post by: Tom on June 22, 2004, 09:03:26 AM

What if I were to double (A) and halve (B)?

Title: Re:Reaction A+B ->C
Post by: Donaldson Tan on June 23, 2004, 12:34:46 PM

A simple substitution into the rate equation would tell you the answer