Chemical Forums
Specialty Chemistry Forums => Chemical Engineering Forum => Topic started by: zeshkani_usa on January 19, 2013, 08:35:45 PM

design a hydraulic holding system for a haybaling system, the system has four cylinders with a 120mm diameter pistons with a stroke of 0.320m, the lines connecting the system are 1cm id(inside diameter). there are 15.5m of lines in the system. for proper design, the reserve tank should hold a minimum of 50% more then the amount of hydraulic fluid in the system, if the diameter of the reserve tank is 30.48cm what is the shortest height it should be?
This question I' am completely stuck on, I have no idea were to start, any pointers would be great
I have the answer but i have no idea how they got it

This sounds like a volume calculation to me  calculate the volume of fluid in the system, add 50%, and that's the total you want in the reserve tank. Then calculate the height, since you know the diameter.

so do you calculate the volume of the cylinder that times 4 since there are 4 cylinders
V=pir^{2}h
V=3619cm^{3} of one cylinder
the volume of the lines are 1217.36cm^{3}
since the tank is going to hold 50% would the volume be 1/2 the over all volume
and for the tank I' am assuming a vertical cylinder, since I' am given the diameter of 30.48cm
would h=V/r^{2}pi so for volume do i add the volume of each cylinder plus the volume of the lines then add 50%more
the correct answer is 32.26cm but i have tried multiple ways of doing it but i cant get the right answer

I got it, i just figured it out
thx for the input