Chemical Forums
Chemistry Forums for Students => High School Chemistry Forum => Topic started by: infinity1 on February 05, 2006, 02:30:17 PM
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I did an experiment where I took extracted C6H5COOH (benzoic acid) from H2O using CH2Cl2. After extraction, I titrated the benzoic acid with NaOH solution. The titration was a light pink, which indicated the acidity of the solution.
The question is: Write the balanced equation for the reaction that occured when you titrated the aqueous layer with NaOH solution.
How do I write this?
If I have to take into consideration the CH2Cl2 and the water, I ended up with something like this:
C6H5COOH + H2O + CH2Cl2 + NaOH --> C6H5COOH + NaOH
where the H2O and CH2Cl2 were removed in order for the NaOH titration to happen.
Is this right? I am not sure. The end product in the experiment is benzoic acid.
Please reply soon. Any help will be greatly appreciated. Thanks.
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C6H5COOH + NaOH --> C6H5COOH
This is neutralization reaction - so you should have salt and water on the right side.
CH2Cl2 and water should be ignored - they don't take part in the reaction (other then water being product).
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Would it look like this:
2 C6H5COOH --> C6H5COOH + NaOH
I did not add water in because both this and CH2Cl2 were removed in order for the titration to proceed, so they don't reallly belong as part of the reaction.
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Where is a salt?
What you have wrote is not a reaction equation, even skeletal.
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The titration was a light pink, which indicated the acidity of the solution.
This completely depends on the indicator you are using. Not all acidic solutions are light pink :P
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I'm a little rusty, but I think the resultant salt produced is a common food preservative?
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I'm a little rusty, but I think the resultant salt produced is a common food preservative?
Not sure if it is still in use, but I remember jars with statement "conserved with ..." from my childhood.
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I guess Canada has less stringent food additive rules. :)
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I guess Canada has less stringent food additive rules. :)
Compared to Polish ones ;) ?
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Where is a salt?
What you have wrote is not a reaction equation, even skeletal.
Then how would you suggest I write it? I have listed every compound used in the experiment. They are C6H5COOH, H2O, NaOH, and CH2Cl2. The salt is NaOH, so I do not know what else you are looking for.
Can someone please guide me through this with constructive suggestions? Thank you.
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This completely depends on the indicator you are using. Not all acidic solutions are light pink :P
Yes, that is true. This is why I said in my first post that I did a titration of C6H5COOH using NaOH. I did not use a standard pH indicator.
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Does anyone know how to do this problem???
I asked a serious question and this thread went completely off base. Someone please provide some constructive guidance.
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The salt is NaOH, so I do not know what else you are looking for.
NaOH is not a salt. It is very basic fact.
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NaOH is not a salt. It is very basic fact.
Chemical pun? Nice. :D
infinity can you determine the products from this neutralization reaction:
C6H5COOH + NaOH -->