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Chemistry Forums for Students => High School Chemistry Forum => Topic started by: jiunshan on February 07, 2006, 08:15:56 PM

Title: Ba2+ + SO42- = BaSO4(s) Calculation
Post by: jiunshan on February 07, 2006, 08:15:56 PM

5.34g of salt of formula M₂SO₄ (where M is a metal) were dissolved in water. The sulphate ion was precipitated by adding excess barium chloride solution when 4.66g of barium sulphate (BaSO₄) were obtained.
a) How many moles of sulphate ion were precipitated as barium sulphate?
b) How many moles of M₂SO₄ were in solution?

a) Barium and sulphate exist in a one-to-one ratio in the compound , so the number of moles of barium sulphate equals the number of moles of sulphate. Beside, how to get the exact value of moles? ???

Title: Re:Calculation
Post by: Mitch on February 07, 2006, 09:09:31 PM

Read line one in my signature.

Title: Re:Calculation
Post by: jiunshan on February 08, 2006, 02:27:29 AM

oops..sorry!
Coz I'm confuse with this question so I donno how to write a equation for this question.
Can somebody help me?

Title: Re:Calculation
Post by: AWK on February 08, 2006, 02:51:24 AM

Ba²⁺  + SO₄^2- = BaSO₄(s)

edit: typo corrected