Chemical Forums
Chemistry Forums for Students => Inorganic Chemistry Forum => Topic started by: K.At.H.Er.I.Ne on February 22, 2006, 10:57:57 AM
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Hi...
Doing a lab report and before i can calculate my yields of the cis and trans [Co(en)2Cl2]Cl i need to get the correct reaction formula!!
I've tried guessing it but i don't even know where to start and i dont want to get it horribly wrong because my mistake'll follow through!.
The steps i took Trans were:
- dissolve CoCl2.6H20 in H2O
- add 10% soln of en
- draw air thru for 10-12 hrs
- add conc HCL
For Cis:
- dissolve some trans isomer in min. 50% aq ethanol
- neutralise w/ NaOH
- evaporate to dryness, repeat
Any help gratefully received!
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4Co(H2O)6++ + O2 + 2H2O -> 4Co(H2O)6+++ + 4OH-
Co(H2O)6+++ + + 2 Cl- -> Co(H2O)4Cl2+ + 2 H2O + 2 en -> [Co(en)2Cl2]+ + 6H2O
What do you think about it?
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Or, to show reaction all in one go:
4CoCl2 + 8en+ O2 + 4HCl -> [4CoCl2en2]Cl + 4H2O
Thus one mole of CoCl2.6H2O (fw 238) gives one mole [CoCl2en2]Cl (fw 285.5)
or, very closely, 1.200 grams of [CoCl2en2]Cl should be obtained per gram of CoCl2.6H2O used.