Chemical Forums
Chemistry Forums for Students => Physical Chemistry Forum => Topic started by: Hunt on February 24, 2006, 07:32:05 PM
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Does anyone know how to mathematically derive the Arrhenius Equation?
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I can tell you that you start with the van't Hoff equation, Vant_Hoff ;D
replacing the Delta H rxn with EA, which is the activation energy.
p.der = partial derivitive
p.der (ln K) / p.der (1/T) = -( Delta H rxn / R )
replacing Delta H rxn with EA gives:
p.der (ln K) / p.der (1/T) = -( EA / R )
by rearranging and integrating both sides you can derive the Arrhenius equation, have a go at doing it and ill work through it with you.
cheers,
madscientist :albert:
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one more hint, the integration constant "C" is represented by A which is somtimes called the pre-exponential factor.
madscientist :albert:
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I'm very grateful to your reply. A good explanation indeed.