Chemical Forums
Chemistry Forums for Students => Physical Chemistry Forum => Topic started by: JayShah on September 18, 2013, 09:58:50 PM
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The volume of a certain liquid varies with temperature as V=V`{0.77 + 3.7 x 10^(-4)(T/K) + 1.52 x 10^(-6)(T/K)^2} where V` is its volume at 298K. Calculate its expansion coefficient, alpha, at 310K.
How am I to go about doing this problem?
alpha is = (1/V)(dv/dt)p
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First, find that derivative.
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First, find that derivative.
Derivative of the equation given? Is the T a variable. After I take the derivative then what do I do? In respect to what variable do I take this derivative?
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dV/dT
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Wow that was stupid easy. Thank you!
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Wow that was stupid easy. Thank you!
If you write the formula correctly