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Chemistry Forums for Students => Physical Chemistry Forum => Topic started by: JayShah on September 18, 2013, 09:58:50 PM

Title: Expansion Coefficient
Post by: JayShah on September 18, 2013, 09:58:50 PM
The volume of a certain liquid varies with temperature as V=V`{0.77 + 3.7 x 10^(-4)(T/K) + 1.52 x 10^(-6)(T/K)^2} where V` is its volume at 298K. Calculate its expansion coefficient, alpha, at 310K.

How am I to go about doing this problem?
alpha is  = (1/V)(dv/dt)p
Title: Re: Expansion Coefficient
Post by: curiouscat on September 19, 2013, 12:07:10 AM
First, find that derivative.
Title: Re: Expansion Coefficient
Post by: JayShah on September 19, 2013, 01:06:22 PM
First, find that derivative.
Derivative of the equation given? Is the T a variable. After I take the derivative then what do I do? In respect to what variable do I take this derivative?
Title: Re: Expansion Coefficient
Post by: curiouscat on September 19, 2013, 01:21:44 PM
dV/dT
Title: Re: Expansion Coefficient
Post by: JayShah on September 19, 2013, 11:24:54 PM
Wow that was stupid easy. Thank you!
Title: Re: Expansion Coefficient
Post by: AWK on November 07, 2019, 09:48:24 AM
Wow that was stupid easy. Thank you!
If you write the formula correctly