Chemical Forums
Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: moores.ac on October 25, 2013, 05:42:52 PM
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Copper Chloride Dihydride + 2(2,4-pentanedione) = Bis(2,4-pentanedionato)copper(II) + 2NaCl + 2H2O
I have 1g of Copper Chloride Dihydride (170.46 g/mol 5.87 mmol 1 equivalent) and 1.22 g 2,4-pentanedione (100.13 g/mol 11.74 mmol 2 equivalents) and have been asked to calculate the exact number of equivalents of 2,4-pentanedione that I will be using by following the instruction to us 1.25 cm3 with a density of 0.975 gm/cm3. How would I do this?
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Copper Chloride Dihydride + 2(2,4-pentanedione) = Bis(2,4-pentanedionato)copper(II) + 2NaCl + 2H2O
I have 1g of Copper Chloride Dihydride (170.46 g/mol 5.87 mmol 1 equivalent) and 1.22 g 2,4-pentanedione (100.13 g/mol 11.74 mmol 2 equivalents) and have been asked to calculate the exact number of equivalents of 2,4-pentanedione that I will be using by following the instruction to us 1.25 cm3 with a density of 0.975 gm/cm3. How would I do this?
What mass of pentan-2,4-dione do you have?
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before starting to calculate anything at all, due to whatsoever systematics:
Copper Chloride Dihydride + 2(2,4-pentanedione) = Bis(2,4-pentanedionato)copper(II) + 2NaCl + 2H2O
this is utterly, utterly wrong
first: one of the substances mentioned doesn't exist at all
second: where does the sodium rightside come from, if there's none whatsoever on the left?
third: sure about the number of water molecules generated / alternatively: all the substances generated mentioned? ( if memory serves , its acetic acid, not water that misses here ... but i don't know for sure about the side conditions you actually did use..)
think:
I have 1g of Copper Chloride Dihydride (170.46 g/mol 5.87 mmol 1 equivalent)
what might this substance mentioned really be ? hint: try to find out which copper compound the MW is belonging to
more general: try to understand what happens there, before putting up a reaction equation, let alone a stoeichiometric one: what happens there, who is deprotonating what, how are those two waters generated, where does the sodiumchloride come from etc etc...
regards
Ingo